Bahasa Inggris Kelas 11 Halaman 8 - 11 [Kunci Jawaban]

 Hello guys, Today we will answer this question "How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?". If you want to know the answer, please read this article. To all students, in this website I will share any answer for any question, like mathematic, Science, Humanities, and Beyond. Lets finish this question.

How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?

How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?

Explanation:

To solve an inequality of the first order (this is one because there isn't a higher exponent of x, than 1), you have to first bring every factor of x to one part, and every number to the other part.

$4-6x\le 2(2x+3)$
$4-6x\le 4x+6$ (apply the distributive property)
$4-6x-6\le 4x+6-6$ (substract $6$ from both sides)
$-2-6x\le 4x$
$-2-6x+6x\le 4x+6x$ (add $6x$ to both sides)
$-2\le 10x$
$\frac{-2}{10}\le \frac{10x}{10}$ (divide both sides by ten${}^{\text{(1)}}$)
$-\frac{1}{5}\le x$
This is your answer, you can flip it if that seams easier:
$x\ge -\frac{1}{5}$

The set of solutions is all the numbers that are greater than or equal to −1/5.

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