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How do you solve for x when you have 4x − 2( 3x − 9) ≤ − 4(2x − 9) ?

 Hello guys, Today we will answer this question "How do you solve for x when you have  4x − 2( 3x − 9) ≤ − 4(2x − 9) ?". If you want to know the answer, please read this article. To all students, in this website I will share any answer for any question, like mathematic, Science, Humanities, and Beyond. Lets finish this question.

How do you solve for x when you have  4x − 2( 3x − 9) ≤ − 4(2x − 9) ?
How do you solve for x when you have  4x − 2( 3x − 9) ≤ − 4(2x − 9) ?


How do you solve for x when you have  4x − 2( 3x − 9) ≤ − 4(2x − 9) ?


Explanation:

Start by distributing the 2 and the -4 on each side of the inequality (multiply the -2 by 3x and by -9; multiple the -4 by 2x and by -9).

That gives you:
4x − 6x + 18 ≤ −8x + 36

Remember, when you multiply the -2 by the -9 on the left, it becomes positive 18.

Since you have 4x - 6x on the left side, you can make that -2x.

Now you have:
−2x + 18 ≤ −8x + 36

Get your variables on one side by adding 8x to both sides, and your numbers on the other by subtracting 18 from both sides and you are left with:
6x ≤ 18

Dividing both sides by 6 gives you the answer:
x ≤ 3