How do you solve for x in 4 − 6x ≤ 2(2x + 3) ?

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 Hello guys, Today we will answer this question “How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?”. If you want to know the answer, please read this article. To all students, in this website I will share any answer for any question, like mathematic, Science, Humanities, and Beyond. Lets finish this question.

How do you solve for x in 4 − 6x ≤ 2(2x + 3) ?
How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?

How do you solve for x in  4 − 6x ≤ 2(2x + 3) ?

Explanation:

To solve an inequality of the first order (this is one because there isn’t a higher exponent of x, than 1), you have to first bring every factor of x to one part, and every number to the other part.
4−6x≤2(2x+3)
4−6x≤4x+6 (apply the distributive property)
4−6x−6≤4x+6−6 (substract 6 from both sides)
−2−6x≤4x
−2−6x+6x≤4x+6x (add 6x to both sides)
−2≤10x
−210≤10x10 (divide both sides by ten(1))
−15≤x
This is your answer, you can flip it if that seams easier:
x≥−15
The set of solutions is all the numbers that are greater than or equal to −1/5.
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